Its molecular weight is 74.44 g, i need 0.025 mole NaOCl solution from 4% aqueous NaOCl . So how many ml should I take ?
Hi
4% solution is 4 gr in 100 ml.
74.44 gr of this material is 1 mole. therefore, 0.0025 mole is 0.1861 gr.
To achive this amount of NaOCl, you want to take 4.6525 ml of this solution to have 0.0025 mole.
Sincerely
First we need to calculate the weight of 0.025 moles of NaOCl.
74.44g.mol-1 x 0.025 mol = 1,861 g
this is the amount of NaOCl (in g) needed to have 0.025 moles of NaOCl, independently of the concentration of the solution.
You have a 4% NaOCl solution, I will take this percentage as w/v (weight to volume ratio). So you have 4g for NaOCl in 100mL of solution, therefore using cross multiplication you will need 46,525mL of this % solution of have 0.025moles of NaOCl.
Edit: In your question you asked first for 0.0025, and later you say something about 0.025 in the body of the text. The calculations shown above are for a 0.025 solution, if you need a 0.0025 solution just divide the final volume by 10 .
Hi
4% solution is 4 gr in 100 ml.
74.44 gr of this material is 1 mole. therefore, 0.0025 mole is 0.1861 gr.
To achive this amount of NaOCl, you want to take 4.6525 ml of this solution to have 0.0025 mole.
Sincerely
Hi
For to prepare the aqueous 4% solution: weigh 4 g of NaOCl and dissolved in 50 mL of water and then slowly add water until all the solution weighing 100 g.
Then, you need to determine the density (d) of the solution with a pycnometer. And then calculate molarity with the equation:
M = 10. (d) %/ A
donde M : molarity (mol/L); 10 = 1000/100 (mL/L); % = weight percentage of NaOCL; and, A = molecular weight of NaOCl.
Finally, the solution volume containing 0.0025 mol from 4% aqueous NaOCl is:
V = 0.0025 mol / M
Sincerely
- Badges
- Science topic
- Similar topics
- Chemistry