Lead acetate solution of .1M and TeO2 dissolved in HCl are prepared having pH 7 and 2 respectively when1:1 proportion are added ppt is formed adding NaOH we get clear solution instead of NaOH how precipitation can be avoided
Or
Just the ways by which pb and Te source material can be prepared to get pbTepbTe
Dear Mr. Anil,
Pb + 2 Cl- = PbCl2 is an instantaneous reaction and Ksp of PbCl2 is 1.7E-5 hence it doesnt get dissolved at any cost. Adding NaOH afterwards is surely disslving the precipitate and it isnt giving you back the Pb.
Hence, the method that you are using is not taking you to the desired final product that you want. You would have to choose some other salt for your process, if possible.
Dear Mr. Dahidesh
means in above Pb will not remain?
But after deposition EDS shows the Pb contain by atomic weight 60% and Te about 40% is indicates that Pb is not getting back or it shows something elese...
Is it possible TeO2 + H2O2 electrolyte prepared and Pb(CH3COO):2H2O both of 0.1M separately and added together will we get required electrolyte to form PbTe
or
TeO2 is scarily soluble in pH between 2 to 7 and having good solubility bet pH 1 to 2 Hence by adding strong acids HCl and HNO3 it will get dissolved but if if you add strong base such as NaOH then also it gets dissolved why this happens?
When you add NaOH reaction like to be Exothermic or else...?
pls
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