For my study I need a solution containing Fe in a concentration of 100 mg/l. I am trying to work out how I create such solution.
It would be most simple to first convert mg/L to mM.
Since the molecular weight of Fe is 55.845, 100 mg Fe/L = 1.79 mM Fe.
If you begin with a stock of 10 mM or 50 mM Fe-EDTA, then it is a simple dilution to make your final solution.
Otherwise, take into account the percentage of the salt that is Fe. For example FeCl3 FW is 162.2, so Fe makes up (55.845/162.2)*100 = 34.43%. You would need 100/.3443 = 290.44 mg FeCl3 to have 100 mg Fe.
You have to know the Fe content of FeEDTA. Or molecular weight. Then 100 x MW/( mass of iron in the edta salt). The unit is mg
According to WHO fortification guidelines, NaFeEDTA contains 13% of iron content. So for 100mg/L fe content one need to add 100*100/13 i.e. 769.23mg of NaFeEDTA per litre.
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