To determine the number of micrograms (μg) of potassium ion formed in 2 grams (g) of K2SO4 (potassium sulfate), we need to consider the molar mass and stoichiometry of the compound.
The molar mass of K2SO4 can be calculated by summing the atomic masses of its constituent elements:
Molar mass of K2SO4 = (2 * atomic mass of potassium) + atomic mass of sulfur + (4 * atomic mass of oxygen) = (2 * 39.10 g/mol) + 32.07 g/mol + (4 * 16.00 g/mol) = 174.26 g/mol
Now, using the molar mass, we can calculate the number of moles of K2SO4:
Number of moles = Mass (g) / Molar mass (g/mol) = 2 g / 174.26 g/mol ≈ 0.01146 mol
Since each K2SO4 molecule contains two potassium ions (K+), the number of moles of potassium ions formed will be twice the number of moles of K2SO4.
Number of moles of K+ ions = 2 * Number of moles of K2SO4 ≈ 2 * 0.01146 mol ≈ 0.02292 mol
Finally, to convert the moles of potassium ions to micrograms, we need to use Avogadro's number and the molar mass of potassium:
Number of micrograms = Number of moles * Avogadro's number * Molar mass (g/mol)
The molar mass of potassium is approximately 39.10 g/mol, and Avogadro's number is 6.022 x 10^23.
Number of micrograms = 0.02292 mol * 6.022 x 10^23 /mol * 39.10 g/mol ≈ 5.433 x 10^21 μg
Therefore, approximately 5.433 x 10^21 micrograms of potassium ions would be formed from 2 grams of K2SO4.
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