I bought few grams of sodium sulfide hydrate (Na2S.xH2O + aq.) with a molecular weight of 78.04 + aq. and assay as (Na2S) of 55-58% as source of sulfur to prepare CdS. I am trying to follow similar previous protocol I found in literature where the authors used 1.4 mmol of Na2S.9H2O (99%) as a source of sulfur. I am little confused about preparing and measuring the accurate amount of Na2S.xH2O that I bought to match the exact amount of (1.4 mmol) of Na2S.9H2O used in previous investigation.
How can I know the exact x value in Na2S.xH2O ?
Should I dry the sodium sulfide hydrate and weigh as Na2S?
Should I assume x = 3 with a M.W of 132.01 g/mol of Na2S.3H2O?
Are there any differences between the two precursors that will effect the purity, morpholog, phase, size, rate of reaction...etc of the final product CdS?
I am looking for your advice.
Regards
Hi Mohammed M. Obeid
I think that won't be any problem if you calculate the molarity of your requirements using the X of your reagent, at the end it's just water, the main factors that can affect the purity, morphology, phase, size, rate of reaction of your CdS are the ratio concentration of your reagents (Na2S.xH2O and CdCl2), type of synthesis, temperature, stirring, time of reaction, etc.
Good luck, Regards!
1.4 M Na2S.9H2O contains 110 g of Na2S.
Dry Na2S.xH2O and weigh the same amount.
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