thank you Mr David, can you please show the calculations of how you arrive to 5.67 ml? I will also be very grateful if you can give in terms of grams

Do You need 10 mole or 10 mmol?

I need 10 mmole

N1v1 =n2v2

v1 = n2v2/n1

v1 = (0.01x1000)/1.765 = 5.67 ml if your reaction volume is 1000ml

6% (W/V) H2O2 in water = 6 g H2O2 in 100 mL of solution (water+H2O2).

Considering that the MW of H2O2 is 34,01 g/mol, in 100 mL of your solution you will have

6/34.01 = 0.17639 mole = 176.39 mmol of H2O2.

To calculate the amount of solution containing the 10 mmol of H202 that you need, you have to resolve this proportion:

176.39 mmol : 100 mL = 10 mmol : x

then

x = 10 * 100 / 176.39 = 5.67 mL

Therefore, you have to add 5.67 mL of H2O2 solution to your reaction.

To convert this amount from mL to g, it is necessary to multiply 5.67 mL by the density of the solution (that should be indicated on the bottle containing it).

this guy Rajashekhar Bathula is a scientist?

This is another question who the guy is asking this question......

thank u