Since coordination compound is formed between metal ion and ligand which have a capacity to accept and gain at least one pair of electron, respectively.
Radical + ML complex = MR + L -https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=&cad=rja&uact=8&ved=2ahUKEwjG-oKmyrv2AhWBzTgGHYVhCq8QFnoECD8QAQ&url=http%3A%2F%2Fwww.eolss.net%2Fsample-chapters%2Fc06%2Fe6-100-04-00.pdf&usg=AOvVaw1oaSNZGU9oy_3GIqItB1no
Radicals can either add to a metal center to establish metal-carbon bonds,\
Organic radicals may interact with transition metal complexes in many different ways, including direct bond formation, atom abstraction, H atom transfer, or addition to ligands.
Dear Yibrehu Bogale Dibabe thank you for posting this important question on RG. It is certainly of broad interest to many other RG members who are interested in coordination chemistry. Free radicals can easily add to coordinatively unsaturated metal complees (coordination compounds). Addition of a carbon-based free radical will form a metal-carbon bond (M–C), while addition of an oxygen-based free radical will for an alkoxide complexes comprising a metal-oxygen bond (M–O). Although it is a bit older, the following article could give you an initial idea:
Recent developments in the coordination chemistry of stable free radicals
http://publications.iupac.org/pac/pdf/2004/pdf/7602x0277.pdf
(please see attached pdf file)
Good luck with your work and best wishes, Frank Edelmann
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