Hi!

I'm performing a RMA with covariate. My data violates the assumption of normality. I tried to transform my data, but that doesn't improve the data. According to my thesis supervisor I should perform the bootstrap method and run it through the syntax. So I did, but SPSS (26) is not giving me confidence intervals??? Any suggestions?

Thanks in advance.

Below my syntax:

BOOTSTRAP

/SAMPLING METHOD=SIMPLE

/VARIABLES TARGET=d60t_slfc d60t_ii d60t_resp d60t_rel d60t_soc INPUT=Zeden_geweld_normaal Primaire_psychopathie_LSRP_subschaal

Secundaire_psychopathie_LSRP_subschaal

/CRITERIA CILEVEL=95 CITYPE=BCA NSAMPLES=1000

/MISSING USERMISSING=EXCLUDE.

GLM d60t_soc d60t_rel d60t_resp d60t_ii d60t_slfc BY Zeden_geweld_normaal WITH

Primaire_psychopathie_LSRP_subschaal Secundaire_psychopathie_LSRP_subschaal

/WSFACTOR=SIPP 5 Polynomial

/MEASURE=persoonlijkheid_functioneren

/METHOD=SSTYPE(3)

/PLOT=PROFILE(SIPP*Zeden_geweld_normaal) TYPE=LINE ERRORBAR=NO MEANREFERENCE=NO YAXIS=AUTO

/EMMEANS=TABLES(SIPP) WITH(Primaire_psychopathie_LSRP_subschaal=MEAN

Secundaire_psychopathie_LSRP_subschaal=MEAN)COMPARE ADJ(BONFERRONI)

/EMMEANS=TABLES(Zeden_geweld_normaal) WITH(Primaire_psychopathie_LSRP_subschaal=MEAN

Secundaire_psychopathie_LSRP_subschaal=MEAN)COMPARE ADJ(BONFERRONI)

/EMMEANS=TABLES(Zeden_geweld_normaal*SIPP) WITH(Primaire_psychopathie_LSRP_subschaal=MEAN

Secundaire_psychopathie_LSRP_subschaal=MEAN)

/PRINT=DESCRIPTIVE ETASQ HOMOGENEITY

/CRITERIA=ALPHA(.05)

/WSDESIGN=SIPP

/DESIGN=Primaire_psychopathie_LSRP_subschaal Secundaire_psychopathie_LSRP_subschaal

Zeden_geweld_normaal.