Could you please tell me how much NaCl is needed to mix in one liter deionised (? NaCl/ 1L deionised water) water to prepare similar EC of soil: water 1:5. In tested soil I found EC 2 dS/m of soil: water 1:5, but I am wondering how much NaCl is needed to mix in deionised water if I want get the same 2 dS/m (EC).
Dear Mohammad Bhuiyan,
If i am not wrong you want 2dS/m of EC in water as same as your soil sample.
Generally speaking soil EC is not only depends on NaCl, it also contributed by other soil ions.
Approximately 1dS/m is equal to 10mM of NaCl. as you want to prepare 2dS/m you have to prepare 20mM NaCl solution.
NaCl molecular weight is 58.43, so adding 58.43gram in 1 lit gives 1 molar solution (1000mM).
and adding 5.843g in 1 lit gives 0.1M (100mM), as you want 20 mM you have to add 1.1686 gram (5.843/5) of NaCl to one liter of water to get approximately 2dS/m.
this value is approximate and this is theoretical only. i hope this helps you
Dear Mohammad,
You should use 1g NaCl. L-1.
I use as reference tables form a book by Richards, 1980
RICHARDS, L.A. Suelos Salinos y Sodicos. Instituto Nacional de Investigaciones Agrícolas. México. 1980. 171p.
I have some publications with a table of concentrations, EC and osmotic potential.
Hope it helps.
Barbara
Dear Barbara,
Thanks for your suggestions. I think that book is Portuguese version. You mentioned that you have some publications with a table of concentrations, EC and osmotic potential. Could you please send me some of them so that I can use as reference.
Regards,
Saiful
Dear Mohammad,
Actually I am not sure how it is called in English, maybe its Molar Ionic Conductivity (σ)! however in french it is called conductivité ionique molaire.
By this, the conductivity of certain solutions can be calculated according to the nature and concentration of ions you have in the solution (NaCl in your case).
the formula is σ (S/m) = Σ λi (S.m^2/mol) x [X]i (mol/m^3)
in your case
σ (S/m) = (λ(Na) x [Na]) + (λ(Cl) x [Cl])
Don't forget to convert units as needed.
You can also see the link http://jf.chene.free.fr/cond_1/cond_1.htm
Hope it helped
Dear Mohammad,
This is in portuguese too, but I think you will understand the table 1.
Thanks a lot @ Hussein Kanbar & Barbara França Dantas for your nice cooperation.
Dear Mohammad Bhuiyan,
If i am not wrong you want 2dS/m of EC in water as same as your soil sample.
Generally speaking soil EC is not only depends on NaCl, it also contributed by other soil ions.
Approximately 1dS/m is equal to 10mM of NaCl. as you want to prepare 2dS/m you have to prepare 20mM NaCl solution.
NaCl molecular weight is 58.43, so adding 58.43gram in 1 lit gives 1 molar solution (1000mM).
and adding 5.843g in 1 lit gives 0.1M (100mM), as you want 20 mM you have to add 1.1686 gram (5.843/5) of NaCl to one liter of water to get approximately 2dS/m.
this value is approximate and this is theoretical only. i hope this helps you
Dear Krishnamoorthy Ramasamy,
Thanks for you suggestions.
Regards,
Saiful
See the following works:
Simon, M., Cabezas, I., García, I., Martinez, P. 1994. .A new method for the estimation of total disolved salts in saturation extracts of soil from electrical conductivity. European Journal of Soil Science, 45, 153-157.
Simon, M. and García, i. 1999. Physico-chemical properties of the soil-saturation extracts: estimaton from electrical conductivity. Geoderma, 90, 99-109.
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