I have an array say A=[1 4 -3 2 4 6 7 8 17 -23 -34 4 5 6
6 7 -5 4 7 41 2 5 23 -3 4 7 7 41 ]
Now I need to get the output as:
[1 4 -3 2 6 7 8 17 -23 -34 5 6 7 -5 4 41 2 5 23 -3 4 7
1 3 1 1 2 1 1 1 1 1 1]
Where the third row gives the count of occurrence of the column (given by first two rows in the output matrix) uniquely.
I did not get exactly the question. So what do you mean by "the count of occurrence of the column (given by first two rows in the output matrix)"
So for example what does each element of third row shows? the third column of third row is 1; does it mean the number of occurrence of -3 or -5 is 1? probably i missed understood some part.
I think the problem as stated is
Given a matrix A2xm , construct a new matrix B3xn such that third row gives the number of count of common columns in A and columns are not repeated in B that is n
thanks all for the response. got the problem solved.
MATLAB14 has an inbuilt function. though I implemented it as:
function output=countcol(input)
output=[];
for i=1:size(input,2)
count=1;
if (isequal(input(:,i),[0;0])==0)
temp=input(:,i);
for j=i+1:size(input,2)
flagt=isequal(input(:,j),temp);
if flagt==1
count=count+1;
input(:,j)=0;
end
end
output=[output [temp;count]];
end
end
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