One possibility is to sort the rows. After that, yo can count easily.

I did not get exactly the question. So what do you mean by "the count of occurrence of the column (given by first two rows in the output matrix)"

So for example what does each element of third row shows? the third column of third row is 1; does it mean the number of occurrence of -3 or -5 is 1? probably i missed understood some part.

I think the problem as stated is

Given a matrix A2xm , construct a new matrix B3xn such that third row gives the number of count of common  columns in A and columns are not repeated in B that is n

thanks all for the response. got the problem solved.

MATLAB14 has an inbuilt function. though I implemented it as:

function output=countcol(input)

output=[];

for i=1:size(input,2)

    count=1;

    if (isequal(input(:,i),[0;0])==0)

        temp=input(:,i);

        for j=i+1:size(input,2)

           flagt=isequal(input(:,j),temp);

               if flagt==1

                   count=count+1;

                   input(:,j)=0;

               end

        end

        output=[output [temp;count]];

    end

end