From a research I got the saturation values of an MH curve in "emuOe/g" but I need them to be in A/m.
My doubt here is is the data in "(emu/g) * Oe" or that "emu" means only "electromagnetic unit" so it's only specifying that the unit of H is in "Oe/g"?
Because otherwise, I saw that from "emu/g" you can convert the data in A/m using the density of the material. But if it is the case of "(emu/g) * Oe" this means that to convert into A/m I have to do for example:
1 [emuOe/g] * density [g/cm3] = 1000/sqrt(4pi) [A/m]
Or am I wrong?
DR Martinelli: To convert emu/g to A/m. Is a two step process. You multiply with the density of the material g/cm^3 to obtain volumetric magnetization emu/cc which 1 ... https://www.researchgate.net/post/How_can_I_convert_emu_gm_into_A_m
https://www.researchgate.net/post/How_do_you_convert_emu_g_to_Ub_mewB_per_TM_atom
Regards--
Hello Dr Ijaz Durrani ,
Thank you for your answer.
Yes I saw that post for converting "emu/g" in "A/m"
But what about "emu Oe/g"?
Regards
DR Martinelli: please have a look at the link:
http://citeseerx.ist.psu.edu/viewdoc/download?doi=10.1.1.204.5001&rep=rep1&type=pdf
Regards-
Dr Ijaz Durrani I'm sorry to bother but I'm still far from understanding as in this document a notation such as "e.m.u. Oe/g" is not treated, and I'm unsure on what to do.
Do you think I should consider it as if it was "Oe * emu/g" or "Oe/g"? Because this is what I have in one of the researches I'm studying.
In another research I even have "emuOe/mol" and "emuG/mol"
I think that in the cgs system the emu is the same as the gauss, so emu/g = 1
The field is then in Oe, which is (10^3)/(4pi) A/m.
See the attached table
In the notes (a) at the bottom it says that in cgs g and emu are the same.
In (h) it says that emu is not a unit, but this probably means it is not a particular unit, or this may only apply to that line..
Thank you so much, I think it doesn't apply only to that line since it is not written again a second time near the same quantity.
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