How can I calculate V2O5 wt% from V as metal% by EPMA?
I analyzed ilmenite by EPMA for V, Co and others (metal%). I want to convert V (2.3 as metal %) to V2O5 wt%; also Co to CoO2
If all the V present in the material (2.3wt%) is in the for of V2O5. Then by simple mathematics you can calculate V2O5 wt. %.
In V2O5, 2 mol of V require 5 mol of O, i.e 0.1 mol (2.3g) of V will require 0.25mol (4g) of O, thus V2O5 is 2.3+4=5.3g. Similarly for Co.
But if all the V or Co is not present in the V2O5 and CoO2 form resp. then its difficult to calculate by this method. In that case I would suggest you to go for XRD.
https://www.jcu.edu.au/advanced-analytical-centre/services-and-resources/resources-and-extras/element-to-stoichiometric-oxide-conversion-factors
I think it is necessary to use the proportion and atomic weights of the elements.
V - at.wt. is 50.94 (V2 at.wt.=101.88)
O - at.wt. is 15.999 (O5 a.wt.=79.995)
V2O5 - mol.wt. is 181.875
Further we make proportion
(V2) 101.88 - X mol.%
(V2O5) 181.875 - 100 mol.%
V2 = (101.88*100)/181.875 = 56,016 mol.%
Then...
(V2) 56.016% - 2.3 wt.%
(V2O5) 100% - X wt.%
V2O5 = (2.3*100)/56.016 = 4.1 wt.%
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