Dear Mohan

According to Mathworks:

Example

Z = [ 1 - 1i     2 + 1i     3 - 1i     4 + 1i

         1 + 2i    2 - 2i      3 + 2i   4 - 2i

         1 - 3i     2 + 3i     3 - 3i    4 + 3i

         1 + 4i    2 - 4i      3 + 4i   4 - 4i ]

P = angle(Z)

P =

-0.7854 0.4636 -0.3218 0.2450

1.1071 -0.7854 0.5880 -0.4636

-1.2490 0.9828 -0.7854 0.6435

1.3258 -1.1071 0.9273 -0.7854

And also you can try the same method for the vector magnitude.

Best,

Hamidreza

http://www.mathworks.com/help/matlab/ref/angle.html

Dear Colleague,

Good Day,

this is the MATLAB code:

clc,clear

a=[1+2*j 2+0.5*j 3-0.8*j 0.2+4*j ]'

mag1=abs(a)

ang1=(180/pi)*angle(a)

overall_mag1=sum(mag1)

overall_ang1=sum(ang1)

This is the results:

a =

1.0000 - 2.0000i

2.0000 - 0.5000i

3.0000 + 0.8000i

0.2000 - 4.0000i

mag1 =

2.2361

2.0616

3.1048

4.0050

ang1 =

-63.4349

-14.0362

14.9314

-87.1376

overall_mag1 =

11.4075

overall_ang1 =

-149.6774

If you need further help or information , please ask.

you can use ->unwrap(angle(Z))               where Z is complex vector.

use matlab help for  unwrap and angle.

you can use ->abs(Z) for magnitude.

If v is the  complex vector, it represents the point in four dims in C4 and its magnitude from origin will be norm(v) and for angle calculation you have to project the vector on one of the plane then from its projection angle can be calculated.  This part may get difficult to visualise. For this you can calculate just the angle between two vectors v1 and v2 as cos(theta) = (v1/norm(v1))^T (v2/norm(v2)). I hope you get your answer.