Step 1: Find the t-critical value. Suppose The t-critical value for α = 0.05, dfw = 36 is 2.028 (I used the TI-83 calculator to find a t-distribution value). Make sure you are using the Within groups DF from your results!

Step 2: Insert the given values, the MSE from your results (I used 26.65 from Within groups on the above table) the t-distribution value from Step 2 into the least significant difference formula:

• LSD = 2.028 √ (26.65 * (2/10)) = 4.68.

Put this number aside for a moment,

Step 3: Calculate ybar1-ybar2 from the results. For this example, we get -8.7.

Step 4: Compare Step 2 and Step 3. If |ybar1-ybar2| ≥ LSD1,2 then you can reject the null hypothesis that the means are the same (H0:μ1 = μ2).

Our value of 8.7 is larger than 4.68 so we can reject the null hypothesis.

Thank you very much Sir