A normal-sense shear zone has a true thickness of 7km. It dips 30º on average. The longitudinal strain-rate is on the order of 10-11 s-1. The duration of extensional movement is around 2-3 m.y.
What may be the total slip along the dip of the shear zone?
Better to install inclinometers and piezometers at many locations and monitor them over time to work out a relationship.
No, Mr. Ravindran, I'm putting my question for an ancient shear zone.
Hello Nirmalya Chatterjee,
interesting question! Attached I have you an interesting literature for the reconstruction of shear zones. It proposes to go the opposite way and first determine the total slip. Here one could exploit the properties of existing long-lived radionuclides. The specified strain rate of (10-11) 10-2 s-1 does not appear to me realistic. In the literature, for the example of reconstruction was determined a shear rate of about 1 cm/a. The shear rate is determines out of the total slip and the determined time duration (in your example 2-3 m.y.). The sum of the shear rates (here cm/a or ε*L/t) results in the total slip, wherein the shear rate (strain rate) over time is not constant.
[The shear rate means the movement in the shear surface. Maybe should the vector of shear rate be divided in part-vectors.]
Look forward and good luck
Michael Lersow
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