Co(NO₃)₂·6H₂O + 12Fe(NO₃)₃·9H₂O + C₆H₈O₇ → CoFe12O19
Find the other products when
Oxygen (O): 6(Co) + 216(Fe) + 6(C) = 228 O atoms on the reactant side,
Hydrogen (H): 12(Co) + 216(Fe) + 8(H from citric acid) = 236 H atoms on the reactant side,
Nitrogen (N): 38(N from ammonium nitrate) = 38 N atoms on the reactant side
Carbon (C): 6(C from citric acid) = 6 C atoms on the reactant side.
BALANCE THE EQUATION WITH PRODUCTS
To balance the chemical equation:
Co(NO3)2⋅6H2O+12Fe(NO3)3⋅9H2O+C6H8O7→CoFe12O19+ProductsCo(NO3)2⋅6H2O+12Fe(NO3)3⋅9H2O+C6H8O7→CoFe12O19+Products
Given the information about the number of oxygen (O), hydrogen (H), nitrogen (N), and carbon (C) atoms on the reactant side, let's balance the equation:
The balanced equation is:
Co(NO3)2⋅6H2O+12Fe(NO3)3⋅9H2O+C6H8O7→CoFe12O19+2Co(NO3)2+24Fe(NO3)3+3H2O+12CO2+6N2Co(NO3)2⋅6H2O+12Fe(NO3)3⋅9H2O+C6H8O7→CoFe12O19+2Co(NO3)2+24Fe(NO3)3+3H2O+12CO2+6N2
- Badges
- Science topic
- Similar topics
- Biological Science
- Bioecology
- Systems Ecology
- Landscape Ecology
- Connectivity