In a closed AC circuit, while the electrons on each limb return during each half cycle, the power doesn't return. Net power is fed into the circuit during each half cycle. In the case of single wire Earth return, one of the half cycles would involve an attempt to push the power through the Earth. The resistance will be higher during this half of the cycle. Does this reduce or increase the lossless capacitative power transfer mechanism?
No inductance or capacitance are ideal, hence there is always power loss. For conduction, the inductance(current sensitive power loss) in form of voltage(drop), vareation of flux with time, V=do/dt=(do/di)(di/dt)= L.di/dt . For non conduction, capacitnce(voltage sensitive power loss) in form of current(leakage)vareation of charge with time I=dq/dt=(dq/dv)(dv/dt)=C.dv/dt.
Bhupendra, The question related to the half of the cycle in which the AC current is being sent through the Earth. Is this cycle more or less efficient than the other cycle when the current is being sent through the conducting wire?
With copper wire, the capacitance effect would gave less power loss( the leakage current)...
I took it that the better the conductor the greater the capacitance.
Where would we actually encounter a single wire earth return?
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