Does anybody how MDA (malonaldehyde) is formed during lipid peroxidation in membrane?
MDA is product of lipid peroxidation. Free radicals attacks polyunsaturated faty acids (PUFA) and lipid radival is formed .
Thank you, but what I asked is ..... are the 3 carbon chain of MDA coming from the 3 carbon fragment sited between two consecutive double bonds in the PUFA?
MDA is a product of peroxidation of omega3 polyunsaturated fatty acid. The degradation occurs from the end of the molecule, so the double bond is the site of chain breakage.
Thanks Ana, this is what I thought, but I do not find any reference accounting for this. Anyway, I have a new doubt. I understand the breakage between two consecutive double bonds of PUFA to yield fragments with oxidized carbon (aldehyde) in both ends of MDA, but I do not understand how the omega CH3 group can be transformed in aldehyde too. Any idea or reference about it?
I am biologist, not a chemist, therefore I cannot exactly answer your question about chemistry of MDA formation. The paper from 1992 (or perhaps 91) by Esterbauer in FRBM should answer your question. There are also few reveiw in Free Radical Research from 2010 about chemistry, biochemistry and biology of the reactive aldehydes.
OK, I will read that reference about the formation of MDA and other hydroxyaldehyde. Thanks again