I have just completed my paper on flyby anomalies and now need to make a prediction of the Juno Oct. 9, 2013 flyby anomaly.
Does anyone here on RG have any knowledge of the following:
V_infty: that is, the incoming Juno speed at infty.
V_prg: that is, the speed of the Juno spacecraft at the perigee.
Theta: that is, the inclination of Juno's orbit relative to the spin axis of the Earth.
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I am surprised that NASA has up to now not published the data of this anomaly. Does anyone have any idea how far NASA has gone in their analysis?
Will be grateful for you responce.
https://drive.google.com/file/d/0B9fNmggd6Al3NzJUUF9ic3dMZ2c/view?usp=sharing
Obtained from Horizons (telnet horizons.jpl.nasa.gov 6775, or http://ssd.jpl.nasa.gov/?horizons)
See the attached image; NAIF/SPICE code to answer this question is here:
https://github.com/drbitboy/ResearchGate_QandA/tree/master/Juno_2013-10
Using V_min for V_infty is a bit loosey-goosey but probably about right.
Let me know if that helps, or if you need any further explanation.
https://github.com/drbitboy/ResearchGate_QandA/tree/master/Juno_2013-10
Brian thanks a lot, this is what I was looking for. The theta=28.006, is that the theta relative to the spin axis of the Earth?
Probably not.
I wrote my code to calculate the "inclination" using the traditional definition: the angle of the Juno orbit plane relative to Earth's equatorial plane.
So that 28.006deg is the angle of the velocity vector at the time of perigee relative to the equatorial plane of earth. The velocity vector at perigee should be a vector in the plane of the orbit and at the maximum angle from the equatorial plane.
So the smallest angle from the orbit plane to Earth's spin axis should be 61.994deg.
The angle between Earth's spin axis and the normal to the orbit plane is again 28.006deg.
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