will product A and B in the file below would be 2-methyl aniline and HCl or will no reaction takes place because AlCl3 is a Lewis acid and electron deficient and will attack on lone pair of NH2 to form an insoluble complex and precipitate out and no reaction takes place. so eventually aniline doesn't undergo Friel crafts reaction in presence of AlCl3 with Ch3Cl?
Dear Noor jaisha Aslam,
As you mentioned, under the Friedel Craft Reaction condition, the aniline (a Lewis base) binds to the electrophile AlCl3 (a Lewis acid) to give a coordination complex (a salt). Then, the positive charge on the nitrogen is electron withdrawing, and it pulls the electron density of the aromatic ring by negative inductive effect (-I effect). It therefore, deactivates the ring for further acylation reactions. Finally, the complex precipitates out of the reaction mixture and the acylation reaction is not observed.
Kind regards.
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