Robeen Ly, the impedance of the Gamry cell at a frequency of 0.1 Hz was measured to be 5500 kohm. This value represents the total impedance of the cell at that frequency, taking into account the cell geometry and the materials used.

The surface area is important for calculating the cell's current density or specific capacitance. These calculations would involve dividing the measured impedance by the cell's surface area. In your case, it does not need to be multiplied by the impedance value.

No,

It is the value you are getting for full or half cell and bulk resistance.

You may compare or create a plot using different surface area.

Qasim Qayyum Kashif

can I use this impedance value (5500 ohm) directly to calculate capacitance in C=1\|Z| equation or not?

Robeen Ly

In order to calculate the capacitance from the impedance value, you need to know the frequency at which the impedance was measured and also make sure that the impedance represents the capacitive part of the overall impedance.

In this case, (data from your question), the impedance value given is 5500 kohm at a frequency of 0.1 Hz.

The equation for calculating capacitance based on impedance and frequency is:

C = 1 / (2πf|Z|)

Now put the given impedance value of 5500 kohm (or 5,500,000 ohms) and the frequency of 0.1 Hz directly in the equation:

C = 1 / (2π(0.1)(5,500,000))

C ≈ 2.9 x 10^-10 F

So, the capacitance would be approximately 290 nF.

The important thing is that this calculation assumes that the impedance value provided is purely capacitive and does not include any resistive components. If the cell has a significant resistive component, this will affect the accuracy of the calculated capacitance, in that case you will have to take resistance in to account to get the accurate capacitance.