Do a Effective Nuclear Charge=Z-S example for a transition metal with "4s1" in its electron configuration without slater's rule?

04 August 2024 0 2K Report

How does having a half-filled 4s1 orbital effect S?

I am guessing something with a half-filled 4s orbital such as Chromium will not be the simple Zeff=24-18. I guess the 4s1 configuration can't be ignored. I don't know how 4s1 configuration affects the Zeff calculation.

Z= protons. S=shielding electrons.

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