Three fair coins are thrown at the same time. Each coin has Head (H) and Tail (T),
From this experience we know that, there is no difference between the results -for example- HTT, THT, TTH,
What's the number of all possible results ?
and if n fair coins are thrown, what's the number of all possible results ?
4 if TTH, THT, HTT - one result, and 8 if TTH, THT, HTT are three different results. For n coins: n+1 and 2n, respectively.
Thanks @Baoulina ,
the reasoning for coins is easer than, dice case,
I would to know what happen is three or $n$ dice are thrown ?
If we consider permutations as different results than 6n; otherwise (n+5)!/(n!*5!)=(n+1)(n+2)(n+3)(n+4)(n+5)/120
Mrs @Baoulina, thnx again,
Last Question,
How we can prove this result ? I mean, the case when the permutations are same.
https://www.mathsisfun.com/combinatorics/combinations-permutations.html
or
https://en.m.wikipedia.org/wiki/Combination
(combinations with repetition)
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