I have been reading a lot of literature which states - to prepare arsenic stock solution, arsenic trioxide is first dissolved in minimum amount of NaOH solution and then made up with the necessary supporting electrolyte and distilled water.  My question is, in my experiments, HCl is the supporting electrolyte and if it is directly soluble in HCl alone, do I have to still dissolve it in minimum amount of NaOH?  I mean, will it make a difference in the results of my electrochemical experiments (stripping voltammetry)? 

Please excuse me if it is a very basic question - I am an electronics engineer... so got disconnected from chemistry a long time ago and Google did not help me much in this aspect.

Thanks in advance.

Sujeevan.

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