I need your help to how change the following Matlab code to plot the vector field as soon as the figure attached (I need plot the Vectors are identical in length) .
%%%%%%%%%%%%%%%%%%%%%%
clear;
sys = @(t,x) [2*x(1)+x(2);x(1)-2*x(2)];
vectfield(sys,-3:0.25:3,-3:0.25:3);
hold on
for x0=-3:1.5:3
for y0=-0.1:1.5:3
[ts,xs]=ode45(sys,[0 5],[x0 y0]);
plot(xs(:,1),xs(:,2));
end
end
for x0=-3:1.5:3
for y0=-3:1.5:3
[ts,xs]=ode45(sys,[0 -5],[x0 y0]);
plot(xs(:,1),xs(:,2));
end
end
hold off
fsize=15;
set(gca,'xtick',[-3:1:3],'FontSize',fsize)
set(gca,'ytick',[-3:1:3],'FontSize',fsize)
xlabel('x(t)','FontSize',fsize) ;
ylabel('y(t)','FontSize',fsize) ;
hold off
%%%%%%%%%%%%%%%
Thank you very much. Please, I need plot the Vectors are identical in length, as soon as the figure attached with my question, quiver(u,v) in Matlb R2014a or Matlab R2017a (for example) Plot the code
%%%
[x,y] = meshgrid(0:0.2:2,0:0.2:2);
u = cos(x).*y;
v = sin(x).*y;
figure
quiver(x,y,u,v)
%%%%
as the figure attached,
Thank you is not enough for you. Please Aparna, can you edit and resubmit the code. because I think the problem is in my Matlab program.
Thank you very much Aparna, I am sorry for what caused you inconvenience. There seems to be a misunderstanding between us, please look at the figures in the attached paper to understand the vector field I mean (which vectors has equal length). The three codes that exist so far do not meet the required purpose, because the vectors almost disappear in the neighborhood of the equilibrium points.
Thanks again for help, I would be very happy if there is any help I can provide you.
Take all the time you need. I have looked for this topic from almost a week ago. I think that these figures has been plotted by Mathematica program or Maple.
Watch the video on the link
https://www.youtube.com/watch?v=5hpzIANoimQ
and run the program8.m file which is the same programe8.m in the video, What is the code problem? Why not run the same way?
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