Hi Anoop, whole-rock Sm/Sm* and Nd/Nd* ratios are calculated in a similar way as Eu/Eu* ratios. For example, the Eu* is calculated by taking the square root of the chondrite-normalized Sm content [in ppm] multiplied by the chondrite-normalized Gd content [in ppm]. For Sm/Sm*, you need to use the chondrite-normalized Nd and Eu contents [in ppm] and for Nd/Nd* the chondrite-normalized Pr and Sm contents, respectively.

Daniel Müller

Sir, Thank you so much for your valuable response.

Dear Anoop K S ,

to calculate Sm/Sm*, Nd/Nd* or Sr/Sr* as well, you should normalize the values to chondrite first (using ppm values from your analysis) and then for Sm*, Nd* or Sr* you should calculate by taking the square root of the elements at the left and right of your element and multiply them. Example:

Sm*= (Nd x Eu)1/2

Nd*= (Pr x Sm) 1/2

Sr*= ....

Eu*= ....

Attached an excel file that maybe can be helpfull

Are you talking about Sm and Nd anomalies, relative to the REE pattern?

I am wondering why are you trying to calculate this. There is no physical reason for Sm and Nd anomalies to exist in natural samples, and as such there is nothing to calculate. If you observe Sm and Nd anomalies in normalised REE plots, most likely is that the data is flawed, or that your normalising values are wrong.

Can you share a paper which mentions those values you are trying to calculate? Then we will have a better idea of what is it exactly that you are trying to achieve.

Michael Anenburg Sir, I am trying to learn whether any relevance is there for using these anomalies in my study. The Paper from which I got this anomaly is attached.

Thank you Gabriele Carnevale for the response.

According to Worrall and Pearson (2001), Eu/Eu* = [(EuN)/(SQR(SmN*GdN)]; Ce/Ce*= [(CeN)/(SQR(LaN*PrN)].

Osama K. Dessouky Thank you sir for the information