Dear all,
As we know that waveguides are by nature "High Pass filters" which allow EM waves with a frequency greater than a cutoff frequency to be transported through it. Owing to such property, I wish to deduce/simulate the loss that a waveguide offers when I do a frequency sweep from low frequency to a very high frequency. To put into numbers, I have simulated a situation which is as follows:
a x b = 40mm x 20 mm
waveguide material = Cu
frequency range = 3GHz to 3THz
plot obtained = Re(Gamma) for TE10 mode.
Attached are the results that I have obtained for the above situation using HFSS. (also included are the theoretical implementation of the same)
My questions are:
1. Is it possible that if I fix only 1 mode in HFSS waveport so there will remain only one mode excited from 3GHz to 3THz? Because when I plot the E-field pattern at different frequencies with only one mode excited, I can see the vectors to be unidirectional till certain frequency, and then as the frequency grows to THz range vectors start to change direction indicating some changes in mode.
2. What does it mean to plot attenuation constant of a particular mode till frequencies very much higher than cutoff. Are there no higher mode effect to be considered here?
3. How this attenuation constant different from insertion loss? As I can see the S21 is very very bad at higher frequency for this waveguide ~400 dB. Is this even possible to use this waveguide with such high insertion loss? Or am I making some mistake here? Is it because the ports are mismatched and we can't compute insertion loss in this configuration?
Any help is appreciable.
Thanks in advance!