It is a Kinematics in one dimensional motion. Asking for average velocity in meter per second squared and in multiples of gravity which is 9.80m/s².
Dear Dr. Impas,
I apologize if I did not understand the question correctly .
In one-dimensional movements maybe the resolution is:
a = ∆v / ∆t = 6500/60
a = 108.333 m/s² , where "a" is the average resultant acceleration produced by engine propulsion.
The vertical displacement of the missile can be calculated with the equation:
S = So + Vo.t + 1/2 . a . t² , So = 0, Vo = 0
S = 1/2 . 108.3 . 60² = 195 000 m (195 Km)
The acceleration of gravity on the equator can be calculated by the law of universal gravitation:
g = G . m / d²
G = 6.67408E-11 m³/kg s² , m = 5.973332E+24 kg ( Earth mass ) ,
d = 6 378 136.6 m. Thus, g = 9.8 m/s²
The acceleration of gravity will decrease at an altitude of 195 000 m:
g = 6.67408E-1 . 5.973332E+24 / (6 378 136.6 + 195 000)² = 9.227 m/s²
I hope this information is useful. Best Regards, Wagner de Godoy
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