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In a large number of papers, thermal conductivity is just given by κe|| = 3.2neTeτe/me = 30692 Te5/2 /(Zi lnΛ) ~2000 and κi|| = 3.9niTiτi/mi = 1249 Te5/2/(Zi 4mi1/2lnΛ) ~ 60 but I don't know how...
24 February 2021 9,502 1 View