"ND sample was first heated in a 9:1 (v/v) mixture of concentrated H2SO4 and HNO3 at 75 °C for 3 days, subsequently in 0.1 M NaOH aqueous solution at 90 °C for 2 h, and then in 0.1 M HCl aqueous solution at 90 °C for 2 h. The resulting carboxylated/oxidized diamonds were extensively rinsed with deionized water and separated by sedimentation...."
Several articles used this method (shown also in the attached file) to create -COOH groups in ND particles surface. However, they didn't explain or illustrate why the second and the third step were used? I well understand that strong acid treatment is needed, but why NaOH? Does anyone know or guess? Thank you in advance.
Hi,
This will neutralise and remove adsorbed H2SO4 (with pretty strong adsorption on ND by the way).
- Badges
- Science topic
- Similar topics
- Filing