What is the explanation that in the amorphous silica appears a peak. If you have an amorphous material won't should appear any peak in the XRD pattern.?????
You have a broad peak in an amorphous material as there is some short range order - there is obviously a fixed distance between bonds in an amorphous material. For example water shows a broad band and the Si-O bond is around the same length in silicates. Crystalline materials with rigid long range order show sharp peaks at fixed Bragg angles.
Show your diffraction pattern please. A sharp peak indicates Bragg diffraction from a crystallite, broad 'peaks' are always present - this is the coherent scattering arising from non-random interatomic distances in the material.
See e.g:
Mozzi R & Warren B (1969) The structure of vitreous silica. J. Appl. Cryst. 2(4):164-172.
Wright AC (1990) Diffraction Studies of Glass Structure. J. Non-Cryst. Solids 123(1-3):129-148.
Mei Q, Benmore CJ, & Weber JKR (2007) Structure of liquid SiO2: A measurement by high-energy x-ray diffraction. Phys. Rev. Lett. 98(5).
Mei Q, Benmore CJ, Sen S, Sharma R, & Yarger JL (2008) Intermediate range order in vitreous silica from a partial structure factor analysis. Phys. Rev. B 78(14):144204.
Alan Fawle is right. Amorphous materials give rise to broad peaks due to the presence of short range order. The peak height decreases rapidly with increasing 2theta.