Using a = 1.0117 nm for cubic In2O3 and 16 atoms per unit cell, I calculate
16 x (1,0117E-7 cm)-3 = 1.55E+22 atoms/cm3.
If I am doping In2O3 at 2%, the concentration would be 0.02 x 1.55E+22 = 3.1E+20 atoms/cm3. Is this correct?
Any references would be helpful.
Hongbin Yang
Agree that the atomic density of In2O3 is 1.55E22.
But I think the In% in In2O3 is 0.4 x 1.55E22.
2% doping is then 0.02 x 0.4 x 1.55E22.
Correct me if I am wrong.
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