the ionization probability as given by A. M. PERELOMOV, V. S. POPOV, and M. V. TERENT'EV in their article "IONIZATION OF ATOMS IN AN ALTERNATING ELECTRIC FIELD", or by Gennady L. Yudin and Misha Yu. Ivanov in their article :"Nonadiabatic tunnel ionization: Looking inside a laser cycle" is dependent on the l and m quantum numbers of the ionized electron. If I want to calculate the ionization probability of the ground state of an Argon atom, what should I use as the l and m quantum numbers of the ionized electron?
The ground state configuration of argon is 4p6; a filled p shell. This will give 1S0 as the ground level. The excited levels will be 4p5 ns and nd. Thus you can take l=1 and ml equal to 0 , +1 and -1.
The ionization of argon will yield 4p5 (2P1/2,3/2) levels. The out going electron will be in the l=0 and l=2 and they will be in the 2P3/2 continuum. For l=0; m=0 and for l=2 you will get m=0,+-1, and +-2.
I hope yuor question has been answered. If you need more information, please write. You may consult a book by R W Cowan or any basic book on atomic physics such as old classic by Herzberg or by White or Beiser for further details.
best wishes,
Aslam
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