There are two leptonic mass matrices obtained while working in Inverse seesaw regime,
1. M\nu = {{0, mD, 0} ,{mDT, 0, M}, {0, MT, \mu}},
2. M\nu = {{0, mDT, 0}, {mD, 0, MT}, {0, M , \mu}}.
After block diagonalizing them we get one of the eigenvalues from each of the above two matrices as,
(a) m\nu = mDM-1 \mu MT^-1mDT
(b) m\nu = mDTMT^-1 \mu M-1mD
Now, how do we explain the phenomenological behaviours shown by the above two matrices(1,2) and their corresponding eigenvalues(a,b).
Biswajoy Brahmachari
If I take the transpose of the first matrix, I am obtaining the second. There is a theorem that transposing does not change eigenvalues. Nothing can be said as such about lepton mixing angles, as it involves diagonalizing also the charged lepton mass matrix.
2 votes
0 thanks
- Badges
- Science topic
- Similar topics
- Physical Sciences
- Theoretical Physics
More Mukta Nihar's questions See All
Similar questions and discussions