The equation was given as follows:
1/ \sqrt (1+β)= \sqrt(1+β)/β
0
The equation obviously has no solution.
What's the problem you've perceived, exactly?
Cas is computer algebra system.
Your factor \sqrt(1-beta) is defined over the reals exactly for beta
You might think that x=x+1 has no solution, but multiply by x-1, simplify, and you get x=1 which has the solution x=1. Amazing!
Thank you very much
for your attention and many thanks for your contributions!
http://www.wolframalpha.com/input/?i=plot:+sqrt(1%2B%CE%B2)+sqrt(1-%CE%B2)%2F%CE%B2%3D+sqrt(1-%CE%B2)%2F+sqrt+(1%2B%CE%B2)
It is " an equivalence transformation on your [but] for beta = 1 it is not, because you multiply with 0"
Who teaches the physics teachers that multiplying by zero is as dangerous as dividing by zero ?
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