In this paper ( http://pubs.acs.org/doi/suppl/10.1021/cm902516f/suppl_file/cm902516f_si_001.pdf ) the calculation of the amount of Zn/S precursor for the first layer ZnS growth on CdS core was as following:

  • The size of CdS core: D0=3.7 nm R0=3.7/2=1.85nm
  • The amount of CdS particles: n1=1.2×10-7 mol
  • The average thickness of one monolayer of ZnS zinc blende (d):  d=0.312 nm
  • The amount of Zn and S precursor of the first layer ZnS (1ML): 
  • The volume of the first ZnS monolayer: V1= 4/3*pi*(R13 - R03) = 1.5684E-26 m3
  • The density of ZnS: For Zinc blende: D=4.10E-3 kg/cm3 = 4.10E+6 g/m3
  • The mass of the 1st ML ZnS shell in one core/shell particle: m=Volume * Density; m=1.5684 E-26 m3 *4.1E6 g/m3= 6.43044 E-20 g
  • M.W. (Molecular weight) of ZnS = 97.474 g/mol
  • The amount of ZnS in one core/shell particle: n2=m/M.W = 6.43044 E-20 g/97.474 g/mol=6.597 E-22 mol/particle
  • Avogadro's constant (N) = 6.025*10E23 particle/mol

In paper the amount of Zn/S precursor for the first layer ZnS growth (A1) was calculated by this method: A1=n1* N *n2 

A1=1.2E-7 mol*(6.025*10E23 particle/mol) *(6.597 E-22 mol/particle) = 0.0477 mmol

But I could not understand why Avogadro's constant (N) was used here. I calculated the amount of Zn/S precursor for the first layer ZnS growth (A1) by different method simply by multiplying the amount of ZnS in one core/shell particle (n2) by the number of CdS core particle (A0): A1 = n2*A0

And here how I calculated A0:

  • The volume of the CdS core: V0= 4/3*pi*(R03) = 2.6522E-26 m3
  • The density of CdS: D=4.87E-3 kg/cm3 = 4.87E+6 g/m3
  • The mass of the CdS core in one core/shell particle: m=Volume * Density; m=2.6522 E-26 m3 *4.87E6 g/m3= 1.2916 E-19 g
  • M.W. (Molecular weight) of CdS = 144.46 g/mol
  • The number of moles per one CdS core particle (n0)= 8.9410E-22 mol/particle
  • the number of CdS core particles (A0) in solution: A0= n1/n0 = 1.2×10-7 mol / 8.9410E-22 mol/particle = 1.3421E14 particles

Then; A1 = n2*A0 = 6.597 E-22 mol/particle * 1.3421E14 particles = 0.000089 mmol

If my method is correct, how can measure in lab this very small number? 

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