I work on synRM and I look for the diagram of the torque after its transformation into dq axes
These are the machine parameters: vs=230*sqrt(2);F=50; ws=2*pi*F; rs=0.12; ld=0.0041; lq=0.0013; p=1;j=0.0159; f=0.0011
Why do I find the couple equal to zero?