Consider 2 input and 2 output for that matter.
inputs taken are 10 and 12V
outputs be 10 and 20V
let the power be 10W and switching freq 10kHz
circuit diagram and associated waveforms attached.
Hi Paul,
As far as I know, the efficiency of any PE circuit is always
(Total Pout) / (Total Pin)
when both are integrated for all circuits across an entire operating cycle.
If you are trying to think of a "partial" form of the definition that applies between specific input and output, then that may be difficult to define for this type of circuit - the reason being that the losses will be "mixed up" or "inter-dependent".
Would be interested to know if you have some specific thing in mind.
Cheers !
-Sanjay
Thanks for your try.
I mean to find the overall efficiency.
Specifically " Can we just add up the individual input powers?"
ie. Pin = Pin1 + Pin2
Pin1 = Vin1 + Iin1
Pin2 = Vin2 + Iin2
or
Should I consider the ON period of Input Sources
ie
from waveform
Pin = [ d3 * Vin2 + (d3-d1) * Vin1 ] * inductor current
Paul,
That is exactly what I said. You should integrate the total input power and total output power output over a single complete operating cycle at steady state.
Now whatever THAT takes !!
I would not rule out simplifications like power summation over time segments (such as the types you are suggesting !), but I would advise caution !!
Particularly in segments where state transitions are taking place between multiple devices, you may end up with wrong results if you go for approximate summations.
Cheers !
-Sanjay
using Pin = [ d3 * Vin2 + (d3-d1) * Vin1 ] * inductor current means that the input current = the inductor current and this is wrong. So, you can simply use matlab simulink to calculate and plot the effeciency Po/Pin having Pin= pin 1 + pin 2 and pin 1,2 = vin1,2 * iin 1,2 and pout in same manner .
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