Hi Alex,

kg/m2/s is the International System of Units (SI) used for precipitation (I suspect you are using data from models)

1kg = 1Liter = 10e6 mm3 and 1m2 = 10e6 mm2

Therfore 1kg of rain over 1 m2 is equivalent to 1mm

So you just need a factor of 86400 (seconds in a day)

1 kg/m2/s = 86400 mm/day

As for mm/3hr this is the accumulated rainfall over 3 hours so you need to sum the 8 values you have for that day to have mm/day

If your data is in netcdf or GRIB i would suggest using the Climate Data Operators which have a python interface :

https://code.mpimet.mpg.de/projects/cdo

https://code.mpimet.mpg.de/projects/cdo/embedded/cdo.pdf

hello Alex,

if you have the precipitation flux/ month, you can use this equation:

Q (mm / mois) = Q (m^3/s) * 1000 * 24 * number of days in the month * 3600 / surface of basin (m^2).

bests

Hi

Let we convert all other units to mm/day. This will be done as follows:

A) 1 kg/m2/s = 86400 mm/day.

B) the sum of 8 Consecutive records of mm/3hr = one record of mm/day.

By these steps you can change the units easly.

Thx

Hi Alex,

kg/m2/s is the International System of Units (SI) used for precipitation (I suspect you are using data from models)

1kg = 1Liter = 10e6 mm3 and 1m2 = 10e6 mm2

Therfore 1kg of rain over 1 m2 is equivalent to 1mm

So you just need a factor of 86400 (seconds in a day)

1 kg/m2/s = 86400 mm/day

As for mm/3hr this is the accumulated rainfall over 3 hours so you need to sum the 8 values you have for that day to have mm/day

If your data is in netcdf or GRIB i would suggest using the Climate Data Operators which have a python interface :

https://code.mpimet.mpg.de/projects/cdo

https://code.mpimet.mpg.de/projects/cdo/embedded/cdo.pdf

Alex Morrison

Reanalysis data are in kg / m2 / s to convert multiply by 8640 for example: 0.0035 x 86400= 302,4 mm / month