If you could have the intensity and voltage delta, then the efficiency of flash lamp according to its nature. Energy can be calculated

Dear Franswa,

welcome,

Your flash lamp emits 40 Joule of energy per cm^2 for a duration of 2 ms.

So, in order to total energy input you need only to know the overall input area.

This depends on the rectangular plate area. You need only to multiply 40 J by the area A in cm^2. But i feel that in this way the question may be an easy one.

Best wishes

Input power :

Power = Voltage * current

Output power :

use a photo diode to find

the intensity at a point radius r

from the lamp then multiply by

the sphere of this radius to

find the total power output.

https://sciencing.com/calculate-light-intensity-7240676.html

Hi Franswa Abraham ,

I would like to highlight that the energy density of a flash lamp is the solution of the integral of the spectral specific intensity over the wavelength - so this value depends strongly on the lower and upper bound values used for calculation (typically defined by the measuring range of the spectrometer used).