I have a copper assembly made of two components and is use for heat transfer. One side or part is completely dipped in dry ice bath. And the second components is at ambient temperature. I need the heat transfer coefficient value for both cases.
You can say that the side which is in the ice has approximately 0oC.
In the otehr side you have heat tranfer with the ambient with a coefficicnt which varies from 5 to 25 W/m2K, somethin that is able to be calculated from Nusselt and it is fully depended on the wind values.
Moreover, there is teh conductivity of the copper but it is can be neglected, because this material has great conductivity.
After these, you can say that the thermal input to the system (from ambient to teh ice) is the next approximatelly:
Q=A*h*(Tambient-0), h=5~25, a typical values is 10.
A is the area of the heat exchange.
As per question, i think setup can be divided into three parts for heat transfer - one is from ambient to copper rod through convection, second is in rod through conduction and last in dry ice through conduction or convection depending upon state of dry ice. In all three section total heat will be equal. Then by equation it can be solve.
- Badges
- Science topic
- Similar topics
- Engineering
- Thermal Engineering
- Thermofluid
- Heat Transfer