In some papers , I have seen E= 1/2 cv^2 and in some papers, E= 1/8 cv^2.So, which formula is applicable to calculate Energy density based on modified GCE as an working electrode? Please help me
It depends on your potential profile during charge-discharge. If the potential increases and decreases linearly showing triangular wave pattern during charge-discharge, then you employ the relation 0.5CV^2.
Hi,
Follow this conservation posted before in RG.
https://www.researchgate.net/post/How_to_calculate_the_energy_density_and_power_density_of_supercapacitor
The energy density should be calculated from a two-electrode cell as a operating device, and the E=1/2CV^2 formula is applied. However, there is an approach, where the results received from 3-electrode cell are used to give a energy/power characterization, making an theoretical 2-electrode symmetric configuration. Therefore, yours electrochemical results are given for a half cell, so the calculations yield a formula E=1/8CV^2.
Please check the other topics on a ResearchGate or other papers like prof. Ruoff's: http://pubs.rsc.org/en/Content/ArticleLanding/2010/EE/c0ee00074d#!divAbstract
- Badges
- Science topic
- Similar topics
- Physical Sciences
- Materials Science
- Materials Chemistry