Dear Researchers,
I have gone through a novel paper (attached) on Bandpass Filter Using Coupled Lines. There author has shown the current distribution in fig6. There, above this fig. author mentions" Along the transmitting region (3.5 GHz), the current distribution is the dominant (Fig. 6(a)). Contrariwise, at 5.6 GHz, the maximal RF current concentrates near the first line, and thus, no energy flows can transmit from the input to output of the filter (Fig. 6(b)). "
How to understand current distribution in Pass band as there also maxm current (red) is in centre..i.e maximum absorption.. ??So how to explain such diagrams...
In my view,power should be more absorbed at middle in stop band and minimum in passband sothat more power can be transmitted toport2.
kindly guide on this issue...
ThanksRegards
Nitin
The filter does not work by absorbing power where the currents are high. It works by reflecting power at the input. There are losses in the filter, but these are small compared to the power transmitted in the passband or reflected in the stopband.
The currents show whether parts of the filter are working as expected, by correctly transforming impedances to the input of the filter that will match or reflect the incoming signal.
When he filter is passing the signal, the centre resonator is resonant and has a large current, which couples the signal through to the output.
When the centre resonator is not resonant the currents in it are small and it doesn't couple well to the output.
Thank you Sir very very much!!! This information is quite helpful to me. Sir i have also sent a message to you. kindly see it.
Once again lot of thanks
Regards
Nitin
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