Potential window offered by aqueous electrolytes is 1.23 V, which is due to the fact that beyond 1.23 V the aqueous electrolytes will undergo electrolysis (common in symmetric supercapacitors). but when the supercapacitor fabricated in asymmetric configuration the aqueous electrolytes tend to provide potential window more than 1.23 V, how it is possible, how the electrolyte is intact without electrolysis, what is the electrochemistry behind? there is report that claims potential window of 2.6 V with 1 M Na2SO4,

can somebody give some into on this?

More Aranganathan Viswanathan's questions See All
Similar questions and discussions