If I have 10 kg of fish and produced 7.5 g ammonia per day from waste.
And according to the data each in literature each 0.57g of ammonia need 1 square meter of biofilter material such as bioballs to convert per day.
That mean this 7.5g ammonia need 13.3m2 of specific surface area of bioballs inside the biofilter tank.
the volume needed from convert this ammonia(7.5g) around 0.0443 m3
0.57g..........need............... 1m2
7.5g ..............need............... ??
Then we need 13.3m2 of specific surface area of bioballs to convert 7.5 g of NH3
If we used bio balls as biofilter materials which is have 600m2/m3 specific surface area and the volume needed from convert this ammonia(7.5g) around 0.0443 m3
The specific surface area 600m2/m3
And can convert as 600m2/1000L
The for 13.2m2
600m2................ 1000L
13.3m2 ...................???
According to the calculation we need 22L from bioballs to convert 7.5 g.
The question is how we can put 22L of bioballs.
I mean put bioballs in container size 22L and fill by bioballs materials or what I must to do.
Hello,
The question stated and the actual enquiry are quite different in my view. You have already calculated the amount. Putting bioballs in a container whose volume is 22 L doesn't make the volume of the biofilter 22 L unless they are somewhat finely ground and fills the container to the brim. Then too it will not be 22 L since the volume stated for the container is for a fluid and not something solid. The best bet for you will be to use a biofilter whose specific surface area: weight ratio is very high, at least five times. It will minimize the load on the filter container itself. Otherwise measure out equivalent weight of the biofilter in pounds or kilograms and use it. You can measure the weight of 22 L water in Kg and then simply put that amount of biofilter media in the filter. The surface area of the filter media is important, but more important is the growth of the nitrifying bacteria since their effective growth rate will directly influence rate of conversion of the ammonia.
Regards,
Dr. Abhishek Mukherjee
Dear Dr Abhishek Mukherjee
Thanks a lot for your answer.
can you explain what your way to have ideal surface area of bioballs or any biofilter materials to remove 7.5 g ammonia per day.
Dear Mr. Al-Tawaha,
You are again looking at the scenario from the not-so-right angle. Do not worry yourself about the biofilter at this point. If the removal of certain amount of ammonia is the prerogative of the study then focus on growing bacterial cultures on any biofilter. Prepare molar solutions of ammonia and allow the cultures to pass through the water or vice-versa. Then check the filtered water for the reduced concentration of ammonia. Highlight the culture that removes more or less the amount in equivalent to your desired rate of removal [for example if a filter removes 17 g of NH3 / day or I Mole ammonia/day then this is more than sufficient]. All you need then is to extrapolate the amount of biofilter needed based on the volume of the filtered water in relation to the volume of the fish pond.
Do not get stuck with the ammonia removal or the fixed weight of the biofilters. Look at the situation from the reverse perspective and you will have a system that will be optimally functional.
Regards,
Dr. Abhishek Mukherjee
Abdel Razzaq M Al Tawaha You can start with the volumetric data and take a wide-mouth measuring beaker to roughly estimate this volume. Again, roughly. So, for a 50% fill volume, take 44 liter reactor. From beaker, fill the media carriers and top it to 22 liters (you can do it in batches for less error). As a rule of thumb, many people start at fill fraction of 0.40-0.55. Now coming to the technicality, the data that you mentioned, i.e., 0.57 g ammonia, we need 1m2 surface area is not true based on volume. Actually, you need to also check the ammonia loading rate per m3. For example, a research done by Harwanto et al, 2011 observed that the areal ammonia removal rates for Kaldness filter media (500 m2/m3) under the ammonia loading rates of 5, 25, and 50 g m-3 day-1 were 64.1, 285.1, and 576.2 mg m-2 day-1, respectively. Hence, you must consider the loading per unit volume of wastewater too while designing. But also, do not forget the rule of thumb. You can also refer my article on MBBR. Best of luck! Article Novel Fluidized-Bed Biofilm Reactor for concomitant removal ...
- Badges
- Science topic
- Similar topics
- Geoscience
- Asia
- India