If pot has been representing a plot, then please measure the area  of pot and calculate the yield of potato per hectare.

Ok, Thank You

The method that you will use depends on the size of the pot.

You can estimate yield by the area of  a single pot (when pots have adequate size), but you can also use plant density (the number of plants per hectare that you should have if potato seeds were sown directly in soil). You multiply yield of a single potato seed by the number of plants per hectare. 

You can calculate in many ways

1. First calculate each potato yield, it helps to calculate mean and statistical significance! 

2. If your pot is more than one sum up the each potato yield per pot and take mean of the pot 

3. Measure the area of your pot 

Example let your pot size is 20m X 20m= Area (400m2)= 0.00 hector b/c one hector equals 10000m2

4. Let your mean yield potato per pot(0.04) = 100kg/0.04hac

5. Know you can convert per hector 

100kg=0.04 hec

X kg =1 hec

The result is 2500kg/hec potato yield 

Dear Dra Phelisa,

The response depends of the pot size as said above, and the aim of the experiment. Comparing treatments: the best decision is to report the response for every treatment in the pots and thus compare them (Mean tests, for example). Otherwise, when the aim is to evaluate the crop yield, the best decision is the field plot evaluation. In my opinion, every pot experiment must be followed by a field plot evaluation where you can have a control and the best treatments from the pot experiment. The responses can be evaluated by EDA methods where every plant represents a replication. Best regards. Walter

This is what I did:

Yield=(Yield per pot/Area of pot) x 10 000 m2

The pots are cylindrical with 21 cm diameter and 30 cm height so my Area is 0.267192 m2.....then I converted that to tons/ha.  I hope it is right.

Thank You Guys for all your responses

Dear Phelisha,

You have to consider what is the usual plant density for potato crop in your country, since plant density is a key factor for total yield and tuber size. It also depends on what propagation material you used, TPS or tubers? According to your pot dimensions, pot area is 0.0346 m2 (π x R2= 3,14 x 0.1052 m), therefore you have 289017 pot (plants) per hectare which seems too dense.

As it is said before, if your goal is to compare different treatments then you can use your method or compare pot yields. Otherwise you have to use plant density as a criterion. 

Phelisa your calculation seems correct.

When growing a crop like potatoes in a pot situation usually the plants are grown on benches and to deal with the plants alley ways are part of the system. When extrapolating greenhouse results compared to field results the alleyways need also be calculated. 

Dear Phelisa, I agree with Walter's comments. There is no method of reliably converting small pot yields to kg/ha. In fact, even in field experimentation plot size is an important consideration. Many biometricians, for example, consider the minimum plot size for maize experiments to be about 100 m2  in fertility experiments. Small plots generally result in higher coefficients of variation and greatly reduced precision. Actually, I cannot see the purpose of converting your pot data --- g/pot presumably --- to kg/ha. This would not be acceptable if the data were to be used in a scientific publication.

However, your data could well provide very valuable information for a subsequent field study.

Kind regards,

Mart.

Dear Phelisa Ndayi

you can estimate yield per ha by multiplying one plant yield *number of plants per ha.

because you must take in consider plants density when you calculate yield per area unit.

best regards

Ali Alhayany

Do not even think of doing such a conversion. It will give you meaningless and misleading results.

To convert yield from a plot to a per ha basis, one multiplies the yield per plot by 10,000 (m2/ha) and divide by the area of the plot (m2/plot). HOWEVER, you will only get a realistic estimate if you have used 'guard rows' in small plots (say under 1000 m2) or the plot is very large. This is because the plants on the edge of the plot gain nutrients, sunlight and water from a greater area than those in the middle of the plot. In the case of using a single pot (not plot) or a single plant, this edge effectr will be so extreme that the projected yield per ha will be total meaningless and misleading. Just presents your results for what they are: yield per pot.

The best solution comes from the combination of the last answers (Michael and Barry). As I mentioned in my previous response, you have to know what is the plant density that is commonly used and simulate it by placing the pots in specific distances to avoid at least shading between plants. However, as Michael pointed out you cannot overcome the edge effect. For example, in my country plant distances are 60-90 cm between rows and 30-40 cm within rows (37037-41666 plant per ha). As you can see, by using pots with 21 cm diameter you do not give sufficient space for tubers to grow, especially considering that many secondary roots have lateral growth.

Therefore try to integrate your results from pots to ha and see what the statistics show. Then you can decide which is the best way to present your data.

Divide the yield per pot by the area of the pot, whatever you get as the answer should then be multiplied by 10,000. Note that the unit to be used in this calculation is Meters (m). So your 1 hectare would be equals to 10,000m2.

Dear Barry Glaz, I agree with your point. It is not recommended to evaluate commercial yield in pots, especially for field crops such as potato. It is also depends on your experimental treatments the decision whether you choose a field or a pot experiment. Pot experiments are easier to manage and allow to better control the environmental factors but are not recommended for commercial yield evaluation where you usually have to carry multiyear field experiments under different locations to counterbalance the environmental effect. In any case though you may have a first idea about relative yields since all your plants are under the same conditions.  

Thank You once again for all your answers

Converting or extrapolating yield from a pot experiment to yield per hectare is not acceptable and hence should not be done.  In addition to edge effects mentioned earlier, the competition for resources (e.g., nutrients, water, lght) that occurs in a field canopy situation is not the same as in pot experiment.

Dear Phelisa,

You have received a number of conflicting answers. However, I guess you will have decided the proper route to take. To some of us it is a no-call, but to others obviously not. What does your head of department say? I did my graduate and post graduate degrees at KZN and would be interested.

Keep well and kind regards,

Mart Farina.

 Yield in (kg)÷pot area×10000 

1 ha = 10000 meters.

If your pot circular then find it's area by formula using for the circle.

you have received several replies so far, however direct translation to hectare is two-way: use of bucket area or soil weight in bucket, a 1ha=2000000kg of soil, or 100m*100m Area, however there are factors to consider before choosing any of the above; soil varies in both space and time, soil reactions in the bucket and field are different, nutrient losses are more predominant in the field and climatic variations in the field

Basing on the above yield can be best translated using the AREA

Nutrient best translated using weight of soil

Dear Phelisa,

You raised an important question and i can see lot of comments. I will not want to re-invent the wheel that is already rolling. I totally agree with the point that asks you to consider the plant density (from Barry). I also agree with the point that advice you to report your yield on the basis of yield per pot. Also, you can just have an idea of what the yield will be in case you are to extrapolate it to the field.

Good luck.

Interesting indeed. However what do you have in mind with the word YIELD?

Potatoes (number, or FW or Dry weight per surface? What surface etc?)

What was the people density when ADAM and EVA were living on EARTH?

Best regards Reto

strasserreto @bluewin.ch

Assuming the planting spacing used for that variety of potato is 40 cm x 20 cm (0.4m x 0.2m = 0.08 m2) and the root weight for pot 1 after harvest is assumed as 900g ( 0.9 kg). The yield for pot 1 is 0.9kg/0.08m2. By simple proportion you can now convert to kg/ha. 1ha = 10000m2.

(10000m2 x 0.9kg)/0.08m2 = 112,500 kg/ha

I'm fully agree with the answer of Baba Salifu Yahaya. You have to keep in mind that this is only valid for comparable conditions, without freeways and buildings on your virtual big area. Good luck. Reto. e-mail: [email protected]

Once one my colleague converted pot yield on per hectare basis and he got exceptionally high yield. He got unrealistic figure. Even 1 m2 plot yield does not give correct answer. Mean plot size for each crop has been available to get approximate yield under hectare basis.

I planted some leafy vegetables on pots, the pots carry 12 kg of soil inside, each pot had 1 plant (leafy vegetable) now I received my yield per plant (g/plant) and I am looking to convert it into kg/ha. My fertilizer application I calculated on the idea of having 2000000 kg of soil in the per hector at the soil depth of 15 cm.

I was thinking of calculating it as follows based on the 2000000 kg of soil idea:

IF: 1 plant is planted on 12 kg soil then how many plants will 2000000 kg soil have

=166666 plants

However, my concern now is that the recommended plant population is around 100000 plants/ha. I am not sure which one I can use to multiply the g/plant so that I can have my yield/ha

I am afraid it is not possible because the extrapolation of your results will hugely shift from the real facts. your pot experiment excluded the competition between plant for all resources, nutrients, water, and light. So don't expect that you will have the same results when you carry out the same experiment in the field.

I am not sure what confusions there;

Let me explain how we can estimate the yield of potato per hector for this experiment

Step 1: Count the number of each potato plant per plot

step 2: Calculate each potato plant yield

Step 3: Convert each potato plant yield per plot

Step 4 : Find the yield of mean potato plant yield per plot

Step 5: Convert the per plot yield to per hectare yield

Example let your plot area is 0.25 m *1.5 m = 0.375 square meter ( just i ignored distance between plant and distance between rows), potato plant per plot is 5, potato plant 1 yield is 10 gm, potato plat 2 yield is 12 gm, potato plant 3 yield is 8 gm, plant 4 yield is 9 gm, plant 5 yield is 15 gm.

The average potato plant yield per plot is 10+12+8+9+15/5= 10.2 gm/0.375

square meter

Therefore, the average potato plant yield per hector is calculated as

if 10.29 gm = 0.375 square meter

x gm = 10,000 square meter

The average potato yield per hectare = 274,400 gm = 274.4 kg

Mind you if you have more than one plot you can following two alternative two ways;

1: Converting each plot potato yield directly to hector then you can estimate the mean product of potato per hectare for your experiment- this good for variance and other statistical analysis showing

2: Estimate the mean potato yield of your all experimental plot and then convert to hector directly.

NB: In order to follow this step you have to have number of potato plant per plot

@Tulu Tolla the problem is that pots and not plots were used