Nice Greeting ,
I have four vectors each one has different length how could I get the average of these vectors in MATLAB?
Thanks in advance
Suppose you have four vectors (A, B, C, and D) with different lengths, you can aggregate them into one vector G as:
G= [A; B; C; D];
Then you can find the average of G as:
mean(G);
Or just sum the components of the vectors and divide by total number of elements.
For example if you have three vectors X={4,5,6} , Y = {10, 11, 9} and Z ={4, 3,5} .
Here, Sum= 57 and total components (n)= 9, Sum/n=6.3
you can also calculate as: For X vector, Sum/3=5, for Y, sum/3= 10, for z, sum/3= 4. Now add these numbers and divide by total number of vectors i.e.3, 19/3= 6.3.
thanks all for answering... I want to get a new vectors for the average , so I have to make the vectors same length first,for example:
A={1,2,3,4,5}
B={1,2,3}
C={1}
then
I want to get a G vector which represent the average as a vector not just one number, Please any assistance will be so appreciated...
Hiba,
Your 3 vectors are in different vector space to it dosenot makes any scene to take their average , but if project all them to same vector space then you can do so.
eq,
A=[1,2,3,4,5] '=> Ap=[1,2,3,4,5]'
B=[1,2,3]' => Bp=[1,2,3,0,0]'
C=[1]' => Cp=[1,0,0,0,0]'
mean([Ap,Bp,Cp],2)={1,4/3,2,4/3,5/3}.
use cells is the easiest way for different vector length
http://www.mathworks.com/help/matlab/ref/cell.html
Hiba,
matlab : Given
A={1,2,3,4,5}
B={1,2,3}
C={1}
x={mean(A),mean(B),mean(C)}
x =
[3] [2] [1]
where x is a cell of matrix elements
To get the matrix back from the cell you have : mat2cell ()
http://www.mathworks.com/help/matlab/ref/cell2mat.html
PS: Any dimensions , I work with huge data elements...
you have two ways to do it
1. use cell
>> A = [1 2 3];
B = [2 3 4 2];
C = [1 2 ];
D = 1 : 5;
ce = {A,B,C,D};
av = cellfun(@mean,ce)
av =
2.0000 2.7500 1.5000 3.0000
2. use matrix
>> A = [1 2 3];
B = [2 3 4 2];
C = [1 2 ];
D = 1 : 5;
E = NaN(4,5);
E(1,1:3) = A;
E(2,1:4) = B;
E(3,1:2) = C;
E(4,1:5) = D;
nanmean(E,2)
ans =
2.0000
2.7500
1.5000
3.0000
I hope this can help you
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