Activation energy at high temperature region corresponds to mobility energy. For mixed conductor, how can we determine the value of mobility energy due to the ion or electron? If we know the transference number, can we calculate the energy value by percentage?
May be you know mixed potential and mixed current density. Try use nerst equation and faraday law.
You can separate the effect by carrying out electrical measurements at low temperature, for which no ionic conduction will take place because of the "freezing" of ion movement. in contrast, electronic conduction will take place, and the low-temperature behaviour will allow to determine the electronic conduction mechanism (and therefore its own activation energy, if relevant).
Alain
Thank you Dr. Nazree for your answer.
Yes, I have yet to determine the potential and current relation of the conductor to find the charge carrier by using nerst equation. If the EMF value obtained how can i relate to the activation energy contribute by the electron and also ion. Thank you.
Thank you Prof. Alain for your suggestion.
Is activation energy at low temperature region for electron same as that at high temperature region. As what i understand, the mobility of the electron process is a temperature activated process, so it maybe different . And by saying low temperature, is that means around room temperature? I measure my sample at 400-1000 degC. Also, how about the energy regarding the cation-vacancy dissociated energy.
Hope someone can help.Thank you.
You need to change the temperature for observing the activated behaviour by application of Arrhenius' law, in which activation energy is obviously a constant. The appropriate range of temperature for observing it is indeed far below room temperature, whereas activation temperature for ionic conductivity is oberved far above room temperature. Therfore it should be easily to separate both contributions.
Alain
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