Since saccade velocity is calculated with the help of fixation points, does it depend on the duration of the stimulus movements and it's location on the screen ? If so how ? Also, saccades velocity always have a value of 100, 200, 400 degrees/second etc, but I do not understand how to obtain such values ? Can anyone demonstrate with an example ?
Thank you
Yes ! Saccade velocity and saccade duration depend on the amplitude of the saccade and therefore on the position of the target with respect to the position of the eyes at the instant when the target appears.
You could find more details in the famous paper by Bahill and others:
Bahill, Clark, Stark. The main sequence a tool for studying human eye movements. Math. Biosci. 24, 191-204 (1975)
It could be of some interest also for what concerns your question about how to compute velocity to read some of my papers:
ZAMBARBIERI D., SCHMID R., MAGENES G., PRABLANC C.: Saccadic responses evoked by presentation of visual and auditory targets, Exp. Brain Res., 47, 417-427, 1982
VERSINO M., GRASSI M., GENOVESE E., ZAMBARBIERI D., SCHMID R., COSI V.: Quantitative evaluation of saccadic eye movements. Effects of aging and clinical use, Neuro-ophthalmology, 12, 327-342, 1992
ZAMBARBIERI D., BELTRAMI G., VERSINO M.: Saccade latency toward auditory targets depends on the relative position of the sound source with respect to the eyes, Vision Res. 35, 3305-3312, 1995
ZAMBARBIERI D.: The latency of saccades toward auditory targets in humans, Progress in Brain Research, 140, 51-59, 2002
Best regards
Daniela Zambarbieri
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