In the frame of image matching, I try to compare two distributions in relying on Earth Mover Distance (EMD). What happens if I consider an image Img1, then I add a constant value to this Img1 to obtain an Image Img2 (just a little bit brighter). Then I compute the two distributions Distr1 and Distr2 of respectively img1 and Img2 (Dist2 is just shifted w.r. to Dist1).  Then I compute EMD distance between Dist1 and Dist2.

Which output can we expect from EMD(Dist1; Dist2)? Is it reasonable to expect EMD=0? because the shape of the two distributions are rigorously similar?

Thank you for any feedback

More Hubert Beaumont's questions See All
Similar questions and discussions